1971C - Clock and Strings - CodeForces Solution


implementation

Please click on ads to support us..

Python Code:

for s in[*open(0)][1:]:a,b,c,d=map(int,s.split());print('YNEOS'[(c-a)*(d-a)*(c-b)*(d-b)>=0::2])


Comments

Submit
0 Comments
More Questions

1424M - Ancient Language
600C - Make Palindrome
1669D - Colorful Stamp
1669B - Triple
1669A - Division
1669H - Maximal AND
1669E - 2-Letter Strings
483A - Counterexample
3C - Tic-tac-toe
1669F - Eating Candies
1323B - Count Subrectangles
991C - Candies
1463A - Dungeon
1671D - Insert a Progression
1671A - String Building
1671B - Consecutive Points Segment
1671C - Dolce Vita
1669G - Fall Down
4D - Mysterious Present
1316B - String Modification
1204A - BowWow and the Timetable
508B - Anton and currency you all know
1672A - Log Chopping
300A - Array
48D - Permutations
677C - Vanya and Label
1583B - Omkar and Heavenly Tree
1703C - Cypher
1511C - Yet Another Card Deck
1698A - XOR Mixup